icantdomath5438 icantdomath5438
  • 21-08-2018
  • Mathematics
contestada

How many positive integers have one less digit than their squares?

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Аноним Аноним
  • 21-08-2018

If we consider numbers of 1 or 2 digits the highest of these is 31, because 31^2 = 961 and 32^2 = 1024. So that gives us all integers between 4 and 31 inclusive. Total 28 integers.

No 3 digits number fits the bill so I think that is the answer

28 positive integers.

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