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  • 24-09-2018
  • Mathematics
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jimrgrant1 jimrgrant1
  • 24-09-2018

r + 2 → B

Factor the numerators/ denominators of both fractions

r² + 7r + 10 = (r + 2)(r + 5)

3r - 30 = 3(r - 10)

r² - 5r - 50 = (r - 10)(r + 5)

the product now becomes

[tex]\frac{(r + 2)(r + 5)}{3}[/tex] × [tex]\frac{3(r - 10)}{(r - 10)(r + 5)}[/tex]

the following factors on the numerators / denominators cancel

3, (r + 5 ) and ( r - 10 ) leaving simplest form

r + 2



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