Answer:
n=11 or n=-3
Step-by-step explanation:
Consider the quadratic equation [tex]n^2-8n-27=6.[/tex]
First, remind the formula
[tex](a-b)^2=a^2-2ab+b^2[/tex]
To complete the square, note that
[tex]8n=2\cdot n\cdot 4[/tex]
Hence, we need [tex]+4^2[/tex]
Add 16 to both sides of equation:
[tex]n^2-8n+16-27=6+16\\ \\(n-4)^2-27=22\\ \\(n-4)^2=49\\ \\n-4=7\text{ or }n-4=-7\\ \\n=11\text{ or }n=-3[/tex]
