Respuesta :

Banabanana

[tex]\tt x^3+4x^2+8x+32\\\\=x^2(x+4)+8(x+4)\\\\=\boxed{\tt(x+4)(x^2+8)}[/tex]

wegnerkolmp2741o

Answer:

(x+4)(x^2+8)

Step-by-step explanation:

x^3 + 4x^2 + 8x + 32

We will factor by grouping

Factor out an x^2 from the first two terms and an 8 from the last two terms

x^2 (x+4) + 8(x+4)

Now we can factor out an (x+4)

(x+4)(x^2+8)