Answer:
[tex]b=\pm 2\sqrt{2}[/tex]
Explanation:
The differential equation which describes the spring mass system is
my''+by'+ky=0
This system will be critically damped if [tex]b^2-4mk=0[/tex] here b is the coefficient of friction m is the mass and k is the spring constant
We have given k=1 and m=2
So [tex]b^2-4\times 2\times 1=0[/tex]
[tex]b^2=8[/tex]
[tex]b=\pm 2\sqrt{2}[/tex]
