astridramirez017988
astridramirez017988 astridramirez017988
  • 25-03-2020
  • Mathematics
contestada

V1 = 70 mL; P1 = ? kPa; P2 = 105 kPa; V2 = 15 mL *

Respuesta :

grayceee
grayceee grayceee
  • 25-03-2020

Answer:

490kpa

Step-by-step explanation:

V1 = 70ml and P1 = ? kpa

V2 = 15ml and P2 = 105kpa

if 15ml will give me 105kpa

then how many times is 70ml greater than 15ml

70/15 = 4.6667

then multiply it by 105kpa

4.6667 * 105 = 490kpa

meaning that if 15ml will give me 105kpa

then 70ml which is (15*4.667) will give 490kpa

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