Answer:
[tex]f(1) = 93[/tex], [tex]f(n) = f(n-1) +4[/tex]
Step-by-step explanation:
The value of f(1) is:
[tex]f(1) = 93 +4\cdot (1-1)[/tex]
[tex]f(1) = 93[/tex]
The values for n and n-1, are respectively:
[tex]f(n-1) = 93 + 4\cdot (n-2)[/tex]
[tex]f(n) = 93 + 4\cdot (n-1)[/tex]
After some algebraic manipulation, the following expression is obtained:
[tex]f(n) = 93 + 4\cdot (n-2) + 4[/tex]
[tex]f(n) = f(n-1) +4[/tex]
