Answer:
f(n) = 4(n-1) + 7
First term
f(1) = 4(1-1) +7 = 0 + 7 = 7
Second term
f(2) = 4(2-1) + 7
= 4(1) + 7 = 4 + 7 =11
Third term
f(3) = 4(3-1) + 7
= 4(2) + 7
= 8 + 7 = 15
Therefore the first three terms of the sequence are 7, 11 and 15.
Hope this helps
