[tex]answer \\ \sqrt{208} \\ solution \\ hypotenuse = c \\ perpendicular = 8 \\ base = 12 \\ using \: pythagoras \: theorem \\ {h}^{2} = {p}^{2} + {b}^{2} \\ or \: {c}^{2} = {8}^{2} + {12}^{2} \\ or \: {c }^{2} = 64 + 144 \\ or \: {c}^{2} = 208 \\ c = \sqrt{208} \\ hope \: it \: helps[/tex]
