[tex]tom \: will \: get \:£166 \\ ben \: will \: get \: £581\\ solution \\ let \: the \: ratios \: be \: 2x \: and \: 7x \\ 2x + 7x = 747 \\ or \: 9x = 747 \\ or \: x = \frac{747}{9} \\ x = £83 \\ replacing \: value \\ 2x \\ = 2 \times 83 \\ = 166 \\ 7x \\ = 7 \times 83 \\ = 581 \\ hope \: it \: helps[/tex]
