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21-07-2020
Mathematics

contestada

what is the initial value for g(x) = 3(1/4)^(x-2) - 3

Respuesta :

s27076272 s27076272

21-07-2020

Answer: g(1) = 9

Step-by-step explanation:

g(x) = 3(1/4)^(x-2) - 3

g(1) = 3(1/4)^(1-2) - 3

g(1) = 3(1/4)^(-1) - 3

g(1) = 3(4) - 3

g(1) = 12 - 3

g(1) = 9

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