siennxieYupgus21 siennxieYupgus21

23-12-2020
Mathematics

contestada

Find the 10th term of the geometric sequence show below
3x^7,9x^9, 27x^11...

PLEASE ANSWER!! TY

Respuesta :

jcherry99 jcherry99

23-12-2020

Answer:

t_10 = 59049 x^25

Step-by-step explanation:

a = 3x^7

r = 3 x^2

t_10 = (3x^7)(3x^2)^10

t_10 = 3x^7 3^(10-1) * (x^2)^(10 - 1)

t_10 = 3x^7 * 3^9 * (x^2)^9

t_10 = 3x^7 * 19683 x^18

t_10 = 59049 x^25

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