Answer:
third option
Step-by-step explanation:
Differentiate using the product rule
Given f(x). g(x) then the derivative is
f(x). g'(x) + g(x). f'(x) ← product rule
Given
[tex]\frac{d}{dx}[/tex](x² secx )
with f(x) = x² and g(x) = secx , then
f'(x) = 2x and g'(x) = secxtanx, thus
[tex]\frac{d}{dx}[/tex](x² secx)
= x². secxtanx + secx. 2x ← factor out xsecx from each term
= xsecx(xtanx + 2) → third option
