Solve x2 – 8x 41 = 0 for x. x = –4 ± 5i x = 4 ± 5i

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24-10-2016
Mathematics

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Solve x2 – 8x 41 = 0 for x. x = –4 ± 5i x = 4 ± 5i

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nobillionaireNobley nobillionaireNobley · Answer 1 · 2016-10-26T21:59:38+02:00

nobillionaireNobley nobillionaireNobley

26-10-2016

x^2 - 8x + 41 = 0
[tex]x = \frac{-(-8)\pm\sqrt{(-8)^2-(4\times41)}}{2}=\frac{8\pm\sqrt{64-164}}{2}\\=\frac{8\pm\sqrt{-100}}{2}=\frac{8\pm10i}{2}=4\pm5i[/tex]

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AngieA AngieA · Answer 2 · 2022-05-27T03:22:38+02:00

AngieA AngieA

27-05-2022

Answer:

It is D.x=4+5i

Step-by-step explanation:

Got it right on edg.2022 <3

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