Answer:
n = 1.14 mol
Explanation:
Hello there!
In this case, according to the ideal gas law:
[tex]PV=nRT[/tex]
It is possible to solve for the moles of the gas given the volume, temperature and pressure:
[tex]n=\frac{PV}{RT}[/tex]
Thus, we plug in 14.0 L, 300 K and 2.0 atm to obtain:
[tex]n=\frac{2.0atm*14.0L}{0.08206\frac{atm*L}{mol*K}*300K}\\\\n=1.14mol[/tex]
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