Answer:
[tex]16^2-(\dfrac{x}{2})^2=(16+\dfrac{x}{2})(16-\dfrac{x}{2})[/tex]
Step-by-step explanation:
The given expression is : [tex]256-\dfrac{x^2}{4}[/tex].
We need to factorize it.
We know that, 16² = 256
So,
[tex]256-\dfrac{x^2}{4}=(16)^2-(\dfrac{x}{2})^2[/tex]
We know that, [tex]a^2-b^2=(a-b)(a+b)[/tex]
[tex]16^2-(\dfrac{x}{2})^2=(16+\dfrac{x}{2})(16-\dfrac{x}{2})[/tex]
Hence, this is the required solution.
