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  • 22-09-2021
  • Mathematics
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What is the value of the expression (e+c-d)x dn when e=-6, n=2, c=6, and d=-1

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Adetunmbiadekunle Adetunmbiadekunle
  • 24-09-2021

The value of the expression (e+c-d)x dn  is -2

The given expression is:

(e+c-d)x dn

e=-6, n=2, c=6, and d=-1

Substitute e=-6, n=2, c=6, and d=-1 into (e + c - d)  x  dn

(e+c-d)x dn  =  [-6  + 6 -(-1)]  x  (-1)(2)

Simplify the expressions in the first and second parentheses

(e+c-d)x dn  =  (0  +  1)   x  (-2)

(e+c-d)x dn  =  1   x  (-2)

Multiply the two terms in the right hand side of the equality sign

(e+c-d)x dn  =   -2

The value of the expression (e+c-d)x dn is -2

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