Respuesta :

rlesandisusanya

Answer:

[tex] \frac{ {2}{y}^{3} {z}^{2} }{x} \\ [/tex]

Step-by-step explanation:

[tex] {({2}^{4} {x}^{ - 4} {y}^{12} {z}^{8} )}^{ \frac{1}{4} } \\ (2 {x}^{ - 1} {y}^{3} {z}^{2} ) \\ \frac{ {2}{y}^{3} {z}^{2} }{x} \\ [/tex]

Step-by-step explanation:

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