v4mpsnots v4mpsnots

22-10-2021
Mathematics

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fernandesnicole981 fernandesnicole981

22-10-2021

Step-by-step explanation:

The given equations are

x2+y3=xy9

⟹xy2y+3x=xy9

⟹3x+2y=9 ........(i)

x4+y9=xy21

⟹xy4y+9x=xy21

⟹9x+4y=21 ........(ii)

Now (i)×3⟶9x+6y=27 .....(iii)

Subtracting (iii) from (ii),

−2y=−6⇒y=3.

Putting y=3 in (i),

3x+2×3=9⟹x=1.∴(x,y)=(1,3)

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