A \pu{1.60 g}1.60 g1, point, 60, space, g calcium supplement contains 37.8\%37.8%37, point, 8, percent \ce{Ca}CaC, a by mass. The calcium is present in the supplement as \ce{CaCO3}(s)CaCOX 3 (s) (molar mass \pu{100.09 g/mol}100.09 g/mol100, point, 09, space, g, slash, m, o, l). How many grams of \ce{CaCO3}(s)CaCOX 3 (s) are in the calcium supplement?

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22-11-2021
Chemistry

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A \pu{1.60 g}1.60 g1, point, 60, space, g calcium supplement contains 37.8\%37.8%37, point, 8, percent \ce{Ca}CaC, a by mass. The calcium is present in the supplement as \ce{CaCO3}(s)CaCOX 3 (s) (molar mass \pu{100.09 g/mol}100.09 g/mol100, point, 09, space, g, slash, m, o, l). How many grams of \ce{CaCO3}(s)CaCOX 3 (s) are in the calcium supplement?

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dsdrajlin dsdrajlin · Answer 1 · 2021-11-26T13:34:36+01:00

A 1.60 g calcium supplement that contains 37.8% Ca by mass, contains 1.51 g of CaCO₃.

We want to calculate the mass of CaCO₃ in a 1.60 g supplement. We need to consider the following relationships.

The mass percent of Ca is 37.8%, that is, there are 37.8 g of Ca every 100 g of supplement.
The molar mass of Ca is 40.08 g/mol.
The molar ratio of Ca to CaCO₃ is 1:1.
The molar mass of CaCO₃ is 100.09 g/mol.

[tex]1.60gSup \times \frac{37.8gCa}{100gSup} \times \frac{1molCa}{40.08gCa} \times \frac{1molCaCO_3}{1molCa} \times \frac{100.09gCaCO_3}{1molCaCO_3} = 1.51gCaCO_3[/tex]

A 1.60 g calcium supplement that contains 37.8% Ca by mass, contains 1.51 g of CaCO₃.

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A 1.60 g calcium supplement contains 37.8% Ca by mass. The calcium is present in the supplement as CaCO₃(s) (molar mass 100.09 g/mol). How many grams of CaCO₃(s) are in the calcium supplement?