natya101 natya101
  • 21-12-2021
  • Chemistry
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20 PIONTS PLZ HELP
What mass of calcium chloride is needed to make 330.0 mL of 0.125 M
solution?

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Scjd
Scjd Scjd
  • 21-12-2021

Answer:

4.58g

Explanation:

1.) What is the molar mass of CaCI2?

= 110.98 g/mol

2.) Find the mols

[tex]conc = \frac{mol}{volume(l)} [/tex]

conc × volume= mol

0.125 M x 0.33 L = 0.04125mol ( 330mL was converted to "L" by dividing 330 by 1000)

3.) The mass(g)

g= mol x atomic weight

g= 110.98g/mol × 0.04125

= 4.58 g

# NOTE M = mol/L

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