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A model for a company’s revenue from selling a software package is R(p)=-2.5^2+700p, where p is the price in dollars of the software. What price will maximize revenue? Find the maximum revenue. What is the price and the maximum revenue in $

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Answer:

Let y = -2.5p^2 + 700p

{Differentiate}

dy/dp = -5p + 700

When dy/dp = 0,

-5p + 700 = 0

-5p = -700

-p = -140

p = 140

Step-by-step explanation:

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