josefcrammer007 josefcrammer007
  • 25-01-2022
  • Mathematics
contestada

the quadratic curve crosses the x axis at 3,0 and the y intercept is 9. express this in the equation y = ax2 + bx + c

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semsee45
semsee45 semsee45
  • 25-01-2022

Answer:

y = ax² - (3a + 3)x + 9

Step-by-step explanation:

The curve passes through 2 points: (3, 0) and (0, 9)

f(3) = 9a + 3b + c = 0

f(0) = 0 + 0 + c = 9

Therefore, c = 9, so plug this into the first equation:

9a + 3b + 9 = 0  

We cannot determine a or b but for a given a we find that

b = - 3a - 3  ⇒  -b = 3a + 3

Therefore, we can express the quadratic curve as:

y = ax² - (3a + 3)x + 9

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