anonymous1947 anonymous1947

25-01-2017
Mathematics

contestada

Solving simultaneous equations with a quadratic, y=2x+5 and y=x^2-x-5

Respuesta :

Jedimaster13 Jedimaster13

25-01-2017

Set equal to eachother:
2x+5=x^2-x-5
0=x^2 - 3x -10
0=(x-5)(x+2)
x = -2, 5

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