villanuevavanvan816
villanuevavanvan816 villanuevavanvan816
  • 22-08-2022
  • Mathematics
contestada


[tex]16y ^{5} - 12y ^{4} + 4y \\ \\ 64 a \times ^{2} - 49ay ^{2} [/tex]
Plss answer this
​

Respuesta :

jimrgrant1 jimrgrant1
  • 22-08-2022

Answer:

see explanation

Step-by-step explanation:

Assuming you require to factorise the expressions

16[tex]y^{5}[/tex] - 12[tex]y^{4}[/tex] + 4y ← factor out 4y from each term

= 4y(4[tex]y^{4}[/tex] - 3y³ + 1)

--------------------------------

64ax² - 49ay² ← factor out a from each term

= a(64x² - 49y²) ← this is a difference of squares and factors in general as

a² - b² = (a - b)(a + b) , then

64x² - 49y²

= (8x)² - (7y)²

= (8x - 7y)(8x + 7y)

then

64ax² - 49ay² = a(8x - 7y)(8x + 7y)

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