we have the polynomial
[tex]p\mleft(x\mright)=x^3+2x^2+9x+18[/tex]For x=-2
the value of p(x) is equal to zero
so
(x+2) is a linear factor
Find out the other factors
Divide
x^3+2x^2+9x+18 : (x+2)
x^2+9
-x^3-2x^2
-------------------------
9x+18
-9x-18
-------------
0
so
x^3+2x^2+9x+18=(x+2)(x^2+9)
Solve the quadratic equation
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