Given the following equation:
[tex]\text{ x}^3\text{ - 27 = 0}[/tex]Let's determine its solution.
We get,
[tex]\text{ x}^3\text{ - 27 = 0}[/tex][tex]\text{ x}^3\text{ = 27}[/tex][tex]\text{ }\sqrt[3]{\text{x}^3}\text{ = }\sqrt[3]{\text{27}}[/tex][tex]\text{ x = 3}[/tex]Therefore, the answer is x = 3.
