lalyaYakosleepre lalyaYakosleepre
  • 24-04-2017
  • Mathematics
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What is the standard form of the equation of the circle x2 - 2x y2 - 8y - 8 = 0?

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Аноним Аноним
  • 24-04-2017
2*2-8-8=0
X*Y-y
You multiply 2 subtract 8 two times
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HomertheGenius
HomertheGenius HomertheGenius
  • 25-04-2017
The standard form of the equation of the circle is:
( x - p )² + ( y - q )² = r²; where p, q are the coordinates of the circle`s center and r is the radius of the circle.
x² - 2 x + y² - 8 y - 8 = 0
( x² - 2 x + 1 ) + ( y² - 8 y + 16 ) - 1 - 16 - 8 = 0
We completed the square of the binomial.
( x - 1 )² + ( y - 4 )² = 1 + 16 + 8
Answer:
The standard form of the equation is ( x - 1 )² + ( y  - 4 )² = 25.
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