heltdyla
heltdyla
24-06-2017
Mathematics
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What is the solutions of x2 = –13x – 4
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Banabanana
Banabanana
24-06-2017
[tex] x^{2} =-13x-4 \\ x^2+13x+4=0 \\ D=b^2-4ac=13^2-4*1*4=169-16=153 \\ x_{1,2}= \frac{-bб \sqrt{D} }{2a} \\ \\ x_1= \frac{-13- \sqrt{153} }{2}=- \frac{13- 3\sqrt{17} }{2} \\ \\ x_2= \frac{-13+ \sqrt{153} }{2}= \frac{3 \sqrt{17} -13}{2} [/tex]
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