izabellaroman23
izabellaroman23 izabellaroman23
  • 25-03-2018
  • Mathematics
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ahmedishaal ahmedishaal
  • 26-03-2018
tanθ + cotθ = 1/sinθcosθ

since we know that;

tan
θ = sinθ/cosθ, and

cot
θ = cosθ/sinθ

now when we add tan
θ and cotθ and replace their values;

tan
θ + cotθ=sinθ/cosθ + cosθ/sinθ

For a common denominator to add those two fractions, the obvious choice is sinθ.cosθ , so

tanθ + cotθ = sin²θ/sinθcosθ + cos²θ/sinθcosθ =sin²θ + cos²θ / sinθcosθ

now we can use the identity that;

sin²θ + cos²θ = 1

So,

tanθ + cotθ = 1/sinθcosθ

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